1000 digits by murky-satyr

o=''
for([,c]in'{{EL\x7fC@qGQMZAUNVeOYenyi}{iZQA^nDRHoMJ]{F||GWU]pp}QLsWIiLpk\\KA^bMA{ZGA@PJWYXBXYShoa[NpmDXRu\\e`[VLQw{qZ~nya}Twx_[g_GONhLDiOCwJ`kksrEpaeggNBGmmyvaetzmUtj^O}ILsr~EZpTj\\mB\x16')o+=c.charCodeAt().toString(2).slice(1)
print(o)

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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