for n in io.lines()do
a={1}m=2 c=0
for i=2,n do
k=1
while c>0 or k<m do t=c+i*(a[k]or 0)c=t/10-t/10%1 a[k]=t%10 k=k+1 end
m=k
end
print(table.concat(a):reverse())end