Find the impostors by rotary-o

var i=0
for(j<-0 to 3103)printf(if(i>{i-=System.in.read%2
i})"(%d, %d) is sus\n"else"No one is sus"*i,j/97,j%97/3)

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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