i,j,k;main(n,c,d){scanf("%d",&n);n=1<<2*n;for(i=2*n;i--;)for(j=2*n;~j--;putchar(~j?"/\\ "[c]:10))for(c=(i^j)/n,k=n;k/=4;c=c<2?(d?j:i)/k%4%3<1^c^d?2:!d:c)d=i/k+j/k&1;}