LED recognition by nu

*a,p,r;x[9];main(k){for(;r=~scanf("%3c%[\n]",&k,2+r?printf(x-p++%3),a=x:x);*a=p%3?k:putchar("58746x93201"[k%11]))k+=*++a/69;}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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