Normal Distribution Table by seichung

f=sprintf;cat("  Z | 0.00",f("   0.0%d",1:9),"\n----+",rep("-",70),sep="");for(z in 0:30/10)cat(f("\n%.1f |",z),f("%.4f",pnorm(z+0:9/100)))

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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