Numloop by nn

i,n;main(u){for(;n<999;i=!printf(u?"Infinity, %2$d\n":"%d, %d\n",i,n))for(u=n++;u&&u-6;i++)u=u%2?u/4:6*u+7;}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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