i,j,k;main(){for(;i<15;printf(j>99|++j>i/2*3+6*i+5?j=k=!++i,"\n":k-i?" "+(j<10):"%d",j))k+=j%3/2-j%5/4;}
Note that non-ascii characters in the above source code will be escaped (such as \x9f).
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