Permutations by uru

#define F(X)for X:=0to 5do
var a,b,c,d,e,f:word;begin
F(a)F(b)F(c)F(d)F(e)F(f)if[a,b,c,d,e,f]=[0..5]then writeln(a,b:2,c:2,d:2,e:2,f:2)end.

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

download

return top