#define F(X)for X:=0to 5do var a,b,c,d,e,f:word;begin F(a)F(b)F(c)F(d)F(e)F(f)if[a,b,c,d,e,f]=[0..5]then writeln(a,b:2,c:2,d:2,e:2,f:2)end.