Relationship ranking by rotary-o

j,k;main(i,s)char*s;{for(;k||gets(s,i=1,j=2);k%s[i++-j/2]||putchar(k?:10))k=s[i]?:s[i=++j/2];}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

To protect the system from spam, please input your favorite sport (hint: I believe its name must start with 'g', case insensitive)

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