Six or more by pooq

int i;int n;int a;int f;for i=17to 9393{n=i;f=1;while n>9{a=n mod 10;n=n/10;if 6>abs(a-n mod 10){f=0;}};if f>0{print i;}}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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