permutation date by nn

main(n,i,v,u){for(1/n?i=v=0:0;n++%100u<"\x09\x1d\x17;;"[i];u-1023||printf("0%d\n",n))main(100*n,i+1,u=1<<n%10|1<<n/10%10|v);}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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