Branching Computations by hallvabo

while 1:
 a=[0]
 for c in raw_input():
\x09b=[];p=1
\x09for e in a:b+=e-1,e+1;p*=e
\x09a=(a[1:],a[:-1],[sum(a)],[p],b)[ord(c)/2%5]
 print`a`.replace("L","")

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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