let rec f n d=print_int(n/(n+d));n+d<d&()=Printf.printf"/%d"(d/(n+d));print_newline()and(!)_=Scanf.scanf"%d/%d "f;!0and(+)a b=try b mod a+a with _->b;;!0
Note that non-ascii characters in the above source code will be escaped (such as \x9f).
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