Find the impostors by KrausRaus

o=""
for(i=0;r=readline();i++)for(j in r)if(escape(r[j])=="%A9")o+="("+i+", "+(j/3|0)+") is sus\n"
print(o||"No one is sus")

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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