Find the impostors by xnor

import os
u=' is sus\n'
print(u.join(`(k/97,k%97/3)`for k,c in enumerate(os.read(0,9999))if ord(c)%2)or'No one')+u

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

To protect the system from spam, please input your favorite sport (hint: I believe its name must start with 'g', case insensitive)

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