HashCode Reversal by test

while 1:
 i=(input()+2**32)%2**32;s=""
 while i:
  c=65
  while(i-c)%31:c+=1
  s=chr(c)+s;i=(i-c)/31
 print s

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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