Inverse problem by pooq

\xd2\xb2\xdd\x82\xcd
\x95\xb6\x8e\x9a\x97\xf1\x93\xfc\x97\xcd
\x95\xb6\x8e\x9a\x90\x94 \x89\xf1\x90\x94\x8ew\x92\xe8
\x93\xfc\x97\xcd\x95\xb6\x8e\x9a\x97\xf1 \x89\xf1\x90\x94 s\x8ew\x92\xe8\x88\xca\x92u\x95\xb6\x8e\x9a
7 \x8a| 7 \x89\xc1 255 and \x88\xea\x95\xb6\x8e\x9a\x95\\x8e\xa6
\x8cJ\x95\xd4

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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