Linux words by chocobi

char s[99];main(i,l,e){for(;gets(s);printf("%d\n",l<5?-1:e))for(e=i=0,l=strlen(s);i<l;++i)e+=(s[i]&31)!=(i<1?12:i<2?9:i>l-2?24:i>l-3?21:14);}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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