Linux words by nn(kou)

c;main(i,p)char*p;{for(;gets(p);printf("%d\n",i-5?-1:c))for(c=i=0;*p;i+=i!=2|!p[2])c+=*p++%32!="\x0c\x09\x0e\x15\x18"[i];}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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