Linux words by nn

c;main(i,p)char*p;{for(;gets(p);c=!printf("%d\n",i>6?c:-1))for(i=2;*p;)c+=*p++%32!="\x0e\x15\x18\x0c\x09"[i++<4?i:p[1]?!p[2]:2];}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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