Linux words by tanakh

char b[];main(a,i,t){for(;gets(b);printf("%d\n",i>4?a:-1))for(a=i=0;t=b[i]&31;)a+=t!="_\x0c\x09\x0e\x15\x18"[++i<3?i:b[i]?b[i+1]?3:4:5];}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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