Normal Distribution Table by nn

END{for(s=.5;i<86;)printf(i>9?i-10?i-15?"-":"+":RS:(i?"   ":"  Z | ")"0.0%d",i++)
for(c=t=.19947115e-4;k<31e3;t=u){if(k%100<1){printf(k%1e3?" ":"\n%.1f | ",k/1e4)
printf("%.4f",s)}u=c/exp(++k*k/2e8)
s+=t+u}}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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