n,o;main(t){for(;t=n-o?t*2:~scanf("%d",&o,n=0);printf("%d %s\n",n,n-o?n>o?">":"<":"=\n"))n+=1e3/(n>o?t:-t)+.5;}
Note that non-ascii characters in the above source code will be escaped (such as \x9f).
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