for n=1,999 do x=n t=0 while 7%x>0 do x=(x%2*x*23+x+2)/4 x=x-x%1 t=t+1 end print((x>1 and"Infinity"or t)..", "..n)end

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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