Roman numeral by inaniwa(not original)

t;N;main(C){for(;read(0,&C,1);t+=(N=N%4999/2)?N-t%N*2:!printf("%d\n",t)-t)N=pow(10,494254%C/9);}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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