Simple Hexagony by McBusLuck

a=(a{0..999})
for((z=2786;d<z;t=x,x+=-1**(d%6/3)*(48**(d%3)%55),s=a[(t+x+z)%z]++%2,d+=5**s));{
printf ${s:d<2}
}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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