Simple Math by rotary-o

enum M{M;System z;{try{for(byte[]a=new byte[14];z.in.read(a)>0;)for(int i=0,j=a[6]-44,k,l;i<6;l=a[i+8]-48,z.out.print(i++<5?(j<-1?k*l:j>2?k/l:k-l*j+10)%10:"\n"))k=a[i]-48;}catch(Exception e){}}}

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