Switzerhegg 2012 by entropix

a=input()
L=list(999*"ggehretsaE")
j=a*10+1
print''.join([(i%j/a>9)*'\n'or((1<<i%j/a/2*5+i/j/a&145536)>0)*' 'or L.pop()for(i)in range(5*a*j)])

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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