The Golden Ratio by *yuko*

byte a(499)
do1 j=8e3,9,-10;k=j/5-1;n=k;do1 i=1,499;k=mod(k,j)*10+n*a(i);1 a(i)=k/j
print'(i0".6"999i0)',a;end

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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