o='' for([,c]in'\xb4!bW1Y00\xcc:D"$8&uH\x00\x1e[OP9>V\xd560>\x1b\x004<.\x1c\xbd\x00\xf4a\x00H\x00H\x00)Y\x03[\x890/6\x00X\x00K&D[K\xd4B!V\xde#$]\xb3\x1fP\x00<LC\x1a#,!&ZV;;\x03_RZ8& \x1a=\x1fc\x1c\x1d\x00\x1aNPC4\x00WBY\xfa\xab\xa9>\x00F \xdd\x00+\xd8\x1a_0>>`\x1f$\x90&\x95KW\x00z\x00"\x00P:W_,6J\x09\xf6\xb9E5@V,1\xf1\x00, \x00M\x861/\x0018:.NU\x00bJ!^*\xd460M\x00B/P[:T<JcXG\xf0\x00L4\xaa93ONS)B\x19>1(KY\x00EF(\x00\x00\x1cy\x00*L\xd9GuMP5\x99\xab)\x00u\x00.B;[.EOW\x1fL\x87<\x00C\x00W0\x00G')o+=c.charCodeAt() print(1.6+o)
Note that non-ascii characters in the above source code will be escaped (such as \x9f).