Twos in Pascals triangle by dianne

f 0=0
f n=f(div n 2)+mod n 2
n%(c:s)=putStrLn(s++tail(do k<-[0..n];x<-show$f k+f(n-k)-f n;c:max"."[x|x>'0'])++s)>>(n+1)%s
main=0%([1..64]>>" ")

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