bubble sort by murky-satyr

d="$System.in".split()*.padLeft(3)
for(n=(d-=d[c=s=0]).size;--n;)n.times{i->d[i]>d[j=i+1]&&[++s,d[i,j]=d[j,i]]
printf'compare =%3d   swap =%3d   data:%s\n',++c,s,d.sum()}

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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