plastic constant by nn

o='1.'
for([,v]in' /\xb39\xf4J<\x19\x09<ZX6/Pa\x03(I\x04((8Z\xad!@5(\x962\x1e\x1c\x1bU|7/;(6E]/b\x11W\x1c')o+=v.charCodeAt()
print(o)

Note that non-ascii characters in the above source code will be escaped (such as \x9f).

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