M plus D equals Y FIXED

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Problem

In the first half of any century, there are so many days in a given year where the number of the month and the number of the day can be summed to equal the last two digits of the year.

Recreate the list below of how many days in each year where this sum occurs.

NB: You do not need to detect leap years to do this task.
NBB: I had to fix it because I finally realized how I messed up the first time.

Options

exec is denied

rejudge feature is enabled

now post-mortem time, all source codes will be revealed

Sample input:_

*NOTHING*

Sample output:

XX02: 1
XX03: 2
XX04: 3
XX05: 4
XX06: 5
XX07: 6
XX08: 7
XX09: 8
XX10: 9
XX11: 10
XX12: 11
XX13: 12
XX14: 12
XX15: 12
XX16: 12
XX17: 12
XX18: 12
XX19: 12
XX20: 12
XX21: 12
XX22: 12
XX23: 12
XX24: 12
XX25: 12
XX26: 12
XX27: 12
XX28: 12
XX29: 12
XX30: 12
XX31: 11
XX32: 11
XX33: 10
XX34: 10
XX35: 8
XX36: 8
XX37: 6
XX38: 6
XX39: 5
XX40: 3
XX41: 3
XX42: 1
XX43: 1

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